"Gotham" is definitely having a good run but can the show get even better if Marilyn Manson was on board?
The rock star has made it known that he is interested in being part of the Fox series, taking to Twitter to drum up support. According to his tweet, not only was he interested in having a role in "Gotham" but that he also believes the audience would love the show more if he was in it. With more than a thousand retweets and over 3,000 favorites, it looks like Manson is on to something.
Even Robin Lord Taylor, who plays Oswald Cobblepot/Penguin on the show, agrees Manson would be a great addition to "Gotham," replying to his tweet with "Um.... YES YES A MILLION TIMES YES." The actor was joined by many others expressing their support for the rock star venturing into Gotham, with some saying that if Manson does land a role, they might even start watching the show.
If that's not a good response, nothing is.
But if Manson does become part of "Gotham," who will he play?
If the Joker makes an appearance in the future, that role is one possibility. Showrunner Bruno Heller did say that Joker's myth will be unveiled in "Gotham" so maybe Manson can also play one of the individuals crucial to the Joker's transformation into a psychotic villain?
If not that, Manson would also make a great Scarecrow, according to one Twitter user, while another sees him in a role leading a motorcycle gang. There's also a vote cast for the rock star to portray the Mad Hatter. Seriously, whatever role Heller puts him in, he's going to fit it perfectly given his image melds so well with the look and feel of "Gotham."
While Manson would appear to be just campaigning for a role, however, there are those who see this as simply teasing fans for what's to come, meaning he's already been cast in the show. Even if that's the case, his "campaign" was generally well-received, meaning "Gotham" made the right choice bringing Manson over to their fold.
Season 2 of "Gotham" premiered Sept. 21.
Be sure to follow T-Lounge on Twitter and visit our Facebook page.